chore: remove legacy inventory stocktake menu and permission configs

inventory-backend/app/__init__.py

@@ -157,6 +157,8 @@ def create_app():
     try:
         from app.services.permission_service import PermissionService
         with app.app_context():
+            # 先清理旧版菜单，再初始化新版
+            PermissionService.cleanup_legacy_stocktake_menus()
             PermissionService.init_audit_menu()
             PermissionService.init_stocktake_menus()
     except Exception as e:

inventory-backend/app/services/permission_service.py

@@ -358,3 +358,33 @@ class PermissionService:
             db.session.rollback()
             print(f"❌ 初始化盘点管理菜单失败: {str(e)}")
             raise e
+
+    @staticmethod
+    def cleanup_legacy_stocktake_menus():
+        """
+        清理残留的旧版库存盘点菜单
+        如果数据库中存在挂在入库管理下的旧版库存盘点菜单，清理掉
+        """
+        try:
+            # 查找可能存在的旧版库存盘点菜单（入库管理下的 stocktake）
+            # 旧版可能在入库管理 (path like '%inventory%stocktake') 或者 code 包含 stocktake 但不是新的
+            legacy_menus = SysMenu.query.filter(
+                SysMenu.code.in_(['stocktake', 'inventory_stocktake_old'])
+            ).all()
+
+            for menu in legacy_menus:
+                # 删除关联的权限
+                SysRolePermission.query.filter_by(target_code=menu.code).delete()
+                # 删除关联的元素
+                SysElement.query.filter_by(menu_code=menu.code).delete()
+                # 删除菜单
+                db.session.delete(menu)
+                print(f"🗑️ 已清理旧版库存盘点菜单: {menu.code} ({menu.name})")
+
+            db.session.commit()
+            return True
+
+        except Exception as e:
+            db.session.rollback()
+            print(f"⚠️ 清理旧版菜单失败: {str(e)}")
+            return False