feat(material): add global floating helper to track latest specification codes with smart grouping

inventory-backend/app/services/inbound/base_service.py

@@ -954,4 +954,71 @@ class MaterialBaseService:
 
         except Exception as e:
             traceback.print_exc()
-            raise e
+            raise e
+
+    @staticmethod
+    def get_latest_specs():
+        """
+        获取所有规格型号的最大连号，按智能分组返回
+        返回格式: [{"group": "S", "latest": "S0115/S0115"}, {"group": "Opt4xxx", "latest": "Opt4018/Opt4018"}, ...]
+        """
+        import re
+
+        # 1. 查询所有不为空的规格型号
+        specs = MaterialBase.query.filter(
+            MaterialBase.spec_model.isnot(None),
+            MaterialBase.spec_model != ''
+        ).all()
+
+        # 2. 数据结构：{分组名: (原始规格, 数字部分)}
+        groups = {}
+
+        def parse_spec(spec_full):
+            """
+            解析规格型号
+            返回: (prefix, num, group_name, original_spec)
+            """
+            # 取斜杠前的部分作为基准
+            base_spec = spec_full.split('/')[0]
+
+            # 使用正则解析：字母前缀 + 数字
+            match = re.match(r'^([A-Za-z]+)(\d+)$', base_spec)
+            if not match:
+                return (base_spec, 0, base_spec, spec_full)
+
+            prefix, num_str = match.groups()
+            num = int(num_str)
+
+            # 智能分组逻辑
+            if prefix == 'Opt':
+                # Opt 按千位段分组
+                thousand = num // 1000
+                group = f"Opt{thousand}xxx"
+            else:
+                # 常规前缀按原值分组
+                group = prefix
+
+            return (prefix, num, group, spec_full)
+
+        # 3. 遍历并分组
+        for material in specs:
+            spec = material.spec_model
+            if not spec:
+                continue
+
+            prefix, num, group, original_spec = parse_spec(spec)
+
+            if group not in groups:
+                groups[group] = (original_spec, num)
+            else:
+                _, existing_num = groups[group]
+                if num > existing_num:
+                    groups[group] = (original_spec, num)
+
+        # 4. 构建返回结果，按分组名排序
+        result = [
+            {"group": group, "latest": spec}
+            for group, (spec, _) in sorted(groups.items())
+        ]
+
+        return result